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x^2-0.25x-0.046875=0
a = 1; b = -0.25; c = -0.046875;
Δ = b2-4ac
Δ = -0.252-4·1·(-0.046875)
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.25)-\sqrt{0.25}}{2*1}=\frac{0.25-\sqrt{0.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.25)+\sqrt{0.25}}{2*1}=\frac{0.25+\sqrt{0.25}}{2} $
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